the sum of the numerator and dinominator of a fraction is 4 more than twice the dinominator if dinominator and numerator are increased by 3 they are in the ratio 2:3 determine the fraction
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let the numerator and denominator be x and y
given that
x+y=2y+4
x-y=4
3x-3y=12 -----------(a)
(x+3)/(y+3)=2/3
3x+9=2y+6
3×-2y=-3-----------(b)
subtracting (a) and (b)
y=-15
x=-11
please recheck the values of x and y
rowley777:
its correct ...thanks a lot
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