The sum of the polynomials p(x) = x - x2 - 2, q(x) = x2-3x+1
Answers
Answered by
0
Step-by-step explanation:
Answer
Correct option is
B
g(x)=x3−3x+1
By remainder theorem,
f(x)=q(x)g(x)+r(x)
∴x5−4x3+x2+3x+1=(x2−1)g(x)+2
⇒(x2−1)g(x)=x5−4x3+x2+3x−1
Now,
x2−1)x5−4x3+x2+3x−1 ( x3−3x+1=g(x)
−x5+−x3
−3x3+x2+3x−1
+−3x3−+3x
x2−1
Answered by
0
Answer:
-2x-1
Step-by-step explanation:
x-x2-2 + x2-3x+1
x-3x-x2+x2-2+1
= -2x-1
hope it's right
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