Math, asked by pavi200666, 1 month ago

The sum of the polynomials p(x) = x - x2 - 2, q(x) = x2-3x+1​

Answers

Answered by itscutegirl12
0

Step-by-step explanation:

Answer

Correct option is

B

g(x)=x3−3x+1

By remainder theorem,

f(x)=q(x)g(x)+r(x)

∴x5−4x3+x2+3x+1=(x2−1)g(x)+2

⇒(x2−1)g(x)=x5−4x3+x2+3x−1

Now,

x2−1)x5−4x3+x2+3x−1 ( x3−3x+1=g(x)

             −x5+−x3

             −3x3+x2+3x−1

             +−3x3−+3x

             x2−1

             

Answered by PranavLute
0

Answer:

-2x-1

Step-by-step explanation:

x-x2-2 + x2-3x+1

x-3x-x2+x2-2+1

= -2x-1

hope it's right

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