Question

The sum of the present age of the father and the son is 46 years. If the age of the father is 11 times the age of the son five years ago, what will be the present age of the son?​

Answer 1

Given :

⬤ Father age is 4 years more than twice the age of his Son .

⬤ Sum of their ages is 46 years .

To Find :

⬤ Present Age of Son .

Solution :

Let :

• Age of Son = x
• Age of Father = 2x + 4

$\sf➦\:{x+2x+4=46}$

$\sf\implies 3x + 4 = 46$

$\sf\implies 3x = 46 - 4$

$\sf\implies 3x = 42$

$\sf\implies x = 42/3$

$\bf\implies x = 14$

Therefore , The Value of x is 21 .

Hence ,

$⇝ \bf Age \: of \:Son = x$

$⇝ \bf = 14$

$⇝ \bf Age \:of \:Father = 2x + 4$

$⇝ \bf = 2(14) + 4$

$⇝ \bf = 28 + 4$

$⇝ \bf = 32$

Therefore , Age of Son is 14 years and Age of Father is 32 years .