The sum of the present ages of A and B is 40 years. After 4 years, the age of A will be 3 times that of B. What is the present age of B?
Answers
Answer:
A is four times as old as B. After 4 years the age of A will be three times as old as B. ⇒ B = 8 years. ∴ The present age of B is 8 years.
Answer:
the present ages of A and B is 8 and 32 respectively.
Step-by-step explanation:
here as per the question,
the present ages of A and Bn add up to 40
which means the sum of their ages is 40.
let the age of A be a yrs and age of B be b years(at present)
so ,
a+b=40
and after 4 years,
he age of A will be 3 times that of B.
which means both ofthem will be 4 years older than their present ages
which means age of a after 4 years is a+4
and age of B after 4 years is b+4
and the relation between them is that age of A will be 4 times that of B.
which implies,
a+4=3(b+4)
a+4=3b+12
a-3b=8
so we will solve the two equations,
on subtracting,
a-a+b-(-3b)=40-8
4b=32
b=8
b represents the age of B which is 8 years.
and substitue the value of b in a+b=40
the age of A is a=32 years
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