Math, asked by aksharrastogi8585, 6 months ago

The sum of the present ages of a father and his son is 60 years. Five years ago, father’s age was four times the age of the son. What is the present age of the son​

Answers

Answered by Aditya9647om
1

Answer:

Let the present ages of son and father be x and (60 -x) years respectively.

Then, (60 - x) - 6 = 5(x - 6)

54 - x = 5x - 30

6x = 84

x = 14.

Son's age after 6 years = (x+ 6) = 20 years..

Answered by labhesh8u92
1

Answer:

Step-by-step explanation:

Let the present age of son be x.

Then, present age of father is (60−x).

According to the question,

⇒  (60−x)−6=5(x−6)

⇒  54−x=5x−30

⇒  54+30=5x+x

⇒  84=6x

⇒  x=  6 /84

⇒  x=14

∴  Son's age after 6 years =(x+6)years

                                           =(14+6)years

                                           =20years.

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