Question

The sum of the present ages of a father and his son is 99 years when the father was as old as his son's is now his age was 4 times age of the sun at that time the ratio of the present age of the son and the father is

Answer 1

Hi there !
Here's the answer:

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¶¶¶ SOLUTION:
Let present Age of father be x
& present Age of son = 9 - x
(°•° Given, Sum of their ages = 9)

Time difference between the two ages
= x - (99 - x) = 2x - 99

When the father was 2x-99 years younger he had the present age of his son i.e., 99 - x

Age of the son in the past = (99 - x) - (2x-99) = 198 - 3x

This age of the son was a quarter of the age of his father:
(99-x) = 4(198-3x)
=> 99-x = 792-12x
=> 12x-x = 792-99
=> 11x = 693
=> x = 63

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Hope it helps