Math, asked by rahul682632, 1 year ago

The sum of the present ages of father and his son is 65 years. Ten years ago the ratio of their ages was 7:2. What will be the ratio of their ages ten years hence?

Answers

Answered by shashankavsthi
3
let the present age of father and son be x and respectively
so according to question

x + y = 65 \\  \frac{x - 10}{y- 10}  =  \frac{7}{2}

2x-20=7y-70
x=(7y-50)/2

put value of x in eq.1 (x+y=65) and get your answer.

rahul682632: after putting the value doesn't get the right answare.the right answare is 11:6.
shashankavsthi: after getting values add 10 then take ratios
Answered by chahat11415
0

let the present age of father and son be x and respectively

so according to question

\begin{gathered}x + y = 65 \\ \frac{x - 10}{y- 10} = \frac{7}{2} \end{gathered}

x+y=65

y−10

x−10

=

2

7

2x-20=7y-70

x=(7y-50)/2

put value of x in eq.1 (x+y=65) and get your answer.

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