The sum of the present ages of mother and her daughter is 56 years. 4 years hence the daughters age will be 1 upon 3 that of the mother what are their present age
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GIVEN:
Sum of present ages of both persons is 56
After 4 years, the daughter will be 1/3 of mother's age
SOLUTION:
Let's first assume the present ages of the daughter and mother to be 'x' and 'y' respectively.
Case l:-
Sum of present ages = 56
==> x + y = 56 --------- (1)
Case ll:-
After 4 years, daughter is 1/3rd of mother's age...
==> 4 + x = 4 + (1/3 × y)
==> 4 + x = 4 + y/3
==> 4 + x = (12 + y)/3
==> 12 + 3x = 12 + y
==> 3x - y = 0
==> 3x = y --------- (2)
Substitute equation (2) in (1),
==> x + (3x) = 56
==> 4x = 56
∴ x = 14
Substitute x = 14 in equation 2,
==> 3(14) = y
∴ y = 42
---> Value of X = 14, Y = 42
∴ Daughter's age is 14 years, Mother's age is 42 years
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