Question

The sum of the present ages of Sibu and Haru is 50 years. Ten years ago Haru was
5 times as old as Sibu. How old are they now?​

Answer 1

X + y = 50. (1)

(x - 10) - 5 (y - 10). (2)

x - 10 - 5y + 50

x - 5y + 40. (3)

elimination of (1) and (3)

x + y = 50

x - 5y = - 40

-. +. +

6y = 90

y = 15

now... substitute y in (1)

x + y = 50

x + 15 = 50

x = 35

(x , y) = ( 35 , 15)

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Answer 2

Answer:

35, 15

Step-by-step explanation:

let sibu present age be x years then hari present age is (50-x)years

ten years ago,

sibu age was (x-10)years

and hari age was (50-x-10)=(40-x)years

A/Q

40-x=5(x-10)

=>40-x=5x- 50

=>40+50=5x+x

=>90=6x

=>x=90/6=15

present age of sibu is 15years and that of hari is (50-15)=35years

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