the sum of the radius of the base and the height of solid cylindrical is 37m if the total sirface area. of the cylinder is 1628 cm squarefind its volume
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given that, (r + h) =37m, and 2πrh =1628 cm sq.
this implies that r= 37-h.....(1)
now, t.s.a. of cylinder = 1628 (given)
so, 2πrh 1628
2π (37-h)h=1628
(37-h)h=1628\2π
(37-h)h= 1628×7/22×2
=37×7
= 259
37h- h^2= 259
h^2 - 37h +259=0
we get, h= 27.51cm or 9.49 cm
so, r=9.49 cm or 27.51 cm
so volume of cylinder= πr^h
= 22×(9.49)^2×27.51/7
= 7,786.58cm^3
or volume of cylinder= 22/7×(27.51)^2 ×9.49
= 22,572cm^3....
this implies that r= 37-h.....(1)
now, t.s.a. of cylinder = 1628 (given)
so, 2πrh 1628
2π (37-h)h=1628
(37-h)h=1628\2π
(37-h)h= 1628×7/22×2
=37×7
= 259
37h- h^2= 259
h^2 - 37h +259=0
we get, h= 27.51cm or 9.49 cm
so, r=9.49 cm or 27.51 cm
so volume of cylinder= πr^h
= 22×(9.49)^2×27.51/7
= 7,786.58cm^3
or volume of cylinder= 22/7×(27.51)^2 ×9.49
= 22,572cm^3....
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