Question

the sum of the reciprocol of kuwali age 3 years ago and 5 years from now is 1/3 find kuwali present age​

Answer 1

Let the present age of Kuwali be x.

• 3 years ago, her age was (x - 3)
• 5 years from now, her age will be (x + 5)

According to the Question,

$\bf{\dfrac{1}{x-3}+ \dfrac{1}{x+5} = \dfrac{1}{3}}\\\\\\\\\implies \sf{\dfrac{(x+5)+(x-3)}{(x-3)(x+5)} = \dfrac{1}{3}}\\\\\\\\\implies \sf{\dfrac{x+5+x-3}{x(x-3)+5(x-3)} = \dfrac{1}{3}}\\\\\\\\\implies \sf{\dfrac{2x+2}{x^{2} -3x+5x-15} = \dfrac{1}{3}}\\\\\\\\\implies \sf{\dfrac{2x+2}{x^{2} +2x-15} = \dfrac{1}{3}}$

$\rm{On\:Cross\:Multiplication,}\\\\\\\sf{3(2x+2)=x^{2} +2x-15}\\\\\\\leadsto \sf{6x+6=x^{2} +2x-15} \\\\\\\longrightarrow \: \sf{6x-2x+6+15=x^{2} }\\\\\\\implies \sf{4x+21=x^{2} }\\\\\\\implies \sf{x^{2} -4x-21=0}\\\\\\\implies \sf{x^{2} -7x+3x-21=0}\\\\\\\implies \sf{x(x-7)+3(x-7)=0}\\\\\\\implies \sf{(x+3)(x-7)=0}$

∴ x = -3 or 7

Age cannot be negative.

∴ Kuwali's Present age = 7 years

Answer 2

Answer:

$\huge\underline\bold\red{Answer}$

$\fbox{7 years is and}$

Step-by-step explanation:

Let the present age of Kuwali =

$x$

3 years ago Kuwali's age = (x-3) years.

5 years later Kuwali's age =(x+5) years.

Now according to the condition:-

$\frac{1}{(x - 3)} + \frac{1}{(x + 5)} = \frac{1}{3}$

$\frac{(x + 5 + x - 3}{(x - 3)(x + 5)} = \frac{1}{3}$

$\frac{2x + 2}{x2 - 3x + 5x - 15} = \frac{1}{3}$

x^ +2x-15=6x+6

x^-4x-21=0

(x+3)(x-7)=0

Either, x+3=6,orx-7=0

thus,x-7 or -3,but age cannot be negative.

hence the present age of Kuwali's is 7 years