Question

The sum
of the roots of a quadratic equation is (2p+1)
and their product is 7p. The equation is?​

Answer 1

Step-by-step explanation:

Given Eqn is

a(2p+1)x

2− b(7p+2)x+ c

7p−3

=02

If this eqn has equal roots Discriminant

D=0

b

2−4ac=0

⇒(7p+2)

2−4(2p+1)(7p−3)=0

⇒49p

2+4+28p−4(149 2−6p−3+7p)=0

⇒49p

2+4+28p−(56p 2−24p−12+28p)=0

⇒49p

2 +4+28p−56p

2−4p+12=0

⇒−7p

2+24p+16=0

⇒7p

2 −24p−16=0

⇒P=4,

7−4

Now Roots At

i)P=4

ii)P= 7−4

Eqn is 9x

2−30x+25=0 Eqn is 7−1x 2+2x−7=03x−5=0x2−14x+49=0

x= 35

x=7