Question

The sum of the roots of equation kx^2-3x+9=0 is 3/5 then the product of roots is

tell step by step answer​

Answer 1

Given:-

• f(x) = kx²-3x+9 = 0
• sum of the roots = $\sf\dfrac{3}{5}$

To find :-

• product of roots

Solution:-

$\implies$ $\sf\dfrac{-(-3)}{k}$ = $\sf\dfrac{3}{5}$

$\implies$ $\sf K$ = $\sf\dfrac{3×5}{3}$

$\implies$ $\sf K = 5$

Now, product of roots = c/a

$\implies$ $\sf product \:of \:zeroes$ = $\sf\dfrac{9}{5}$

Answer 2

Answer:

9/5 is the answer to the question.