The sum of the roots of the equation px^21qx+r=0 are equal to the sum of their squares show that 2pr=pq+r^2
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Given question is px² + qx + r = 0 then show that 2pr = pq + q²
Exp:-
Let its roots be a and b
a + b = -q / p ab = r / p
a + b = a² + b² given
=>. ( a + b ) = ( a + b )² - 2ab
=>. - q / p = q² / p² - 2 ( r / p)
=>. 2rp = qp + q²
Given question is px² + qx + r = 0 then show that 2pr = pq + q²
Exp:-
Let its roots be a and b
a + b = -q / p ab = r / p
a + b = a² + b² given
=>. ( a + b ) = ( a + b )² - 2ab
=>. - q / p = q² / p² - 2 ( r / p)
=>. 2rp = qp + q²
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