The sum of the roots of the equation x2 + px + q = 0 is equal to the sum of their squares,
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Step-by-step explanation:
as per question
Let a & b are the roots
Now
a + b= -P & a x b = q
given that
a+b= a^2+ b^2
⇒ a + b = (a + b)^2 -2ab
⇒ -P = (-P)^2 -2q
⇒ -P = P^2 -2q
⇒ P^2 + P - 2q = 0
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