the sum of the roots of the quadratic equation 2 x² + ( 2k – 1 ) x – ( k - 4 ) = 0 is equal to the product of its roots , then the value of k is : *
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Step-by-step explanation:
given eq is 2x^2+(2k-1)x-(k-4)=0------>ax^2+bx+c=0
sum of roots= -b/a = -(2k-1)/2
product of roots=c/a=-(k-4)/2
given (1-2k)/2 = (4-k)/2
1-2k=4-k
k= -3
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