the sum of the series is -8,-6,-4...n terms is 52. the number of terms n is
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-8, -6, -4....... n ( Given sequence)
here a=-8 , t2=-6 and t3=-4
d=t2-a=-6+8=2
t3-t2=-4+6=2
Here, common difference (d) =2 is constant .
Hence the given sequence is in A. P
Sn=52......... (Given)
therefore, by formula.
Sn=n/2[2a+(n-1) d
52=n/2[2×-8+(n-1) 2
52×2=n[-16+2n-2]
104=n[-18+2n]
104=n-18+2n
104+18=n
122=n
Therefore, Number of terms are 122.
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