The sum of the square of three consecutive odd number is 83 ,find the number
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ans=3
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x² + (x+2)² + (x+4)² =83
x²+x²+4+4x+x²+16+8x = 83
3x²+12x+20-83 = 0
3x²+12x-63 = 0
x²+4x-21 = 0
x²+7x-3x-21 = 0
x(x+7)-3(x+7) = 0
(x-3) (x+7)
x = 3 , -7
consecutive odd numbers are 3, 5, 7
x²+x²+4+4x+x²+16+8x = 83
3x²+12x+20-83 = 0
3x²+12x-63 = 0
x²+4x-21 = 0
x²+7x-3x-21 = 0
x(x+7)-3(x+7) = 0
(x-3) (x+7)
x = 3 , -7
consecutive odd numbers are 3, 5, 7
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