The sum of the square of three consecutive odd number is 83, find the number
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The numbers are 3, 5 and 7
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Let three consecutive odd no's are x,x+2,x+4...
According to Q's: x^2+(x+2)^2+(x+4)^2=83
=> x^2+x^2+2x+4+x^2+8x+16= 83
=> 3x^2+10x+20-83=0
=> 3x^2+10x-57=0
=> 3X^2-9x+19x-57= 0
=> 3x(x-3)+19(x-3)=0
=> (3x+19)(x-3)=0
=> x= 3
Hence numbers will be 3,5,7
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