Question

The sum of the square of two consecutive multiples of 7 is 637 find the multiples​

Answer 1

Answer:

Check attachment for your answer.

Answer 2

Answer:

14 and 21

Step-by-step explanation:

x^2+ (x+7)^2= 637

solve the quadratic

2 x^2+ 14x-588=0.

x^2+7x-294=0

(-7(+/-)35)/2 are the solutions of the quadratic

ignoring the negative value of solution, x=( 35-7)/2=14

x+7=21

therefore the multiples are 14 and 21.

cheers mark brainliest