Question

the sum of the square of two numbers is 80 and the square of their differences is 36..the product of two numbers is---------

Answer 1

hope this will help you

Answer 2

let first number is x and second number is y

so according to first condition ,

x^2 + y^2 = 80 ------ ( 1 )

according to second condition ,

( x - y ) ^2 = 36

x^2 - 2xy + y^2 = 36

x^2 + y^2 - 2xy = 36

80 - 2xy = 36 ----- from (1)

-2xy = - 44

xy = 22

so the product of the two is 22