Question

the sum of the squares if three consecutive odd numbers is 2531​

Answer 1

Answer:

StepLet the middle odd number be x.

The 3 consecutive odd numbers will be (x-2), x, (x+2)

(x-2)^2 + x^2 + (x+2)^2 = 2531

=> x^2 + 4 -2x + x^2 + x^2 +4 +2x = 2531

=> 3x^2 + 8 = 2531 [Cancelling 2x, -2x]

=> 3x^2 = 2523

=> x^2 = 841

=> x = +29, -29 [For even -order root, every positive integer has two roots]

Therefore, the consecutive odd numbers could be 27, 29, 31 or -31, -29, -27.

As the question didn’t mention positive odd numbers, hence the answer lies in ambiguity.

Ans. +31/-27-by-step explanation:

Answer 2

Answer:

Step-by-step explanation:

→ Let the numbers be x, x + 2 and x + 4.

→ Then, x2+(x+2)2+(x+4)2=2531

=> 3x2+12x−2511=0

=> x2+4x−837=0

=> (x - 27) (x + 31) = 0  

=> x = 27.

→ Hence, the required numbers are 27, 29 and 31.