The sum of the squares of 2 consecutive positive integers is 420. Find the integers.
Answers
Answered by
1
Let the numbers be x and x+1
according to question,
(x)2 + (x+1)2 = 421
x2 + x2+1+2x = 421
2x2 + 2x =420
diving the whole equation be 2
x2 + x = 210
x2 +15x -14x -210 =0
x(x+15) - 14(x+15) =0
(x+15)(x-14)=0
since it s a natural number, x should be positive
therefore, x=14 and x+1=15
the required numbers are 14 and 15.
according to question,
(x)2 + (x+1)2 = 421
x2 + x2+1+2x = 421
2x2 + 2x =420
diving the whole equation be 2
x2 + x = 210
x2 +15x -14x -210 =0
x(x+15) - 14(x+15) =0
(x+15)(x-14)=0
since it s a natural number, x should be positive
therefore, x=14 and x+1=15
the required numbers are 14 and 15.
Similar questions