Question

the sum of the squares of 3 consecutive positive number is 365​

Answer 1

let the numbers be x-1,x,x+1

so sum of their squares =>

x²+2x+1+x²+x²+1-2x = 365

=> 3x²+2= 365

=> 3x² = 363

=> x² =121

=> x = 11

so the numbers are 10, 11 and 12.

hope it helps☺️