Question

The sum of the squares of 3 consequetive odd numbers is 251. The numbers are

Answer 1

Step-by-step explanation:

Let the nos. be x, x+2, x+4.

Given,

x^2+(x+2)^2+(x+4)^2=251

x^2+(x^2+4+4x)+(x^2+16+8x)=251

3x^2+12x+20=251

3x^2+12x-251+20=0

3x^2+12x-231=0

3(x^2+4x-77)=0

x^2+4x-77=0

x^2+11x-7x-77=0

x(x+11)-7(x+11)=0

(x-7)(x+11)=0

x=7,-11

When x=7, x+2=9, x+4=11

When x=-11, x+2=-9, x+4=-7

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