Question

The sum of the squares of the zeroes of the polynomial x^2_5x+8is

Answer 1

Answer: 9

Step-by-step explanation:

x^2-5x+8 , let it's zeroes be m, n

Then, m+n = -b/a= -(-5) /1=5

and mn= c/a= 8

We know that,

m^2+n^2= (m+n)^2-2mn= (5) ^2- 2 ×8

= 25-16= 9

The sum of the squares of the zeroes = 9