Question

the sum of the squares of three consecutive numbers is 110. determine the numbers ​

Answer 1

Answer:

Hope it helps you dear

Step-by-step explanation:

let the consecutive no. be x,x+1 ,x+2

So,x^2 + ( x+1)^2+(x+2)^2 = 110

x^2+x^2+1+2x+x^2+4 + 4x = 110

3x^2+6x+5=110

3x^2+6x =105

3x^2+6x-105 =0

3( x^2+2x-35) = 0

x^2+ 7x-5x -35= 0

x(x+7) -5(x+7)=0

(x+7) (x-5) =0

x = -7,5

-7 is neglected.....

so, x=5

x+1= 5+1=6

x+2=5+2=7