Question

the sum of the squares of three consecutive odd number is 2531 find the numbers

Answer 1

Hey

Here is your answer,

Let the numbers be x, x + 2 and x + 4.

Then, x2+(x+2)2+(x+4)2=2531

=> 3x2+12x−2511=0
=> x2+4x−837=0
=> (x - 27) (x + 31) = 0
=> x = 27.

Hence, the required numbers are 27, 29 and 31.

Hope it helps you!

Answer 2

Answer:

Step-by-step explanation:

Given :-

The sum of the squares of three consecutive odd number is 253.

To Find :-

The numbers.

Solution :-

Let the numbers be x, x + 2 and x + 4.  

According to the Question

⇒ x² + (x + 2)² + (x + 4)² = 2531  

⇒ 3x² + 12x - 2511 = 0    

⇒ x² + 4x - 837 = 0  

⇒ (x - 27) (x + 31) = 0  

⇒ x = 27.  

Hence, the required numbers are 27, 29 and 31.