Question

The sum of the squares of three numbers is 138, while the sum of their products taken two at a time is 131. Their sum is:

Answer 1

Let a,b,c be the 3 numbers then acc to q we have,

a^2 + b^2 + c^2 =138 & ab+bc+ca =131

(a+b+c)^2 = a^2 + b^2 + c^2 + 2(ab+bc+ca) =138+2*131 =400

Hence, a+b+c =√400 = 20

Answer 2

Answer:

their the sum is

the answer is 20