The sum of the squares of two numbers is 233 and one of the numbers is 3 less than twice the other number. Find the numbers.
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Answered by
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Let the first no. be x and the other be 2x - 3
Then, according to given question, we have
x(square) + 2x - 3(square) = 233
i.e 5x(square) - 12x -224 = 0
Solving this, we get
x = 8 and the other no.
i.e 2x - 3 = 2(8) - 3 = 13
Then, according to given question, we have
x(square) + 2x - 3(square) = 233
i.e 5x(square) - 12x -224 = 0
Solving this, we get
x = 8 and the other no.
i.e 2x - 3 = 2(8) - 3 = 13
Phillipe:
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