Question

the sum of the squares of two numbers is 233. one of the number is 3 less than twice the other number.fine the 2 numbers.

Answer 1

let the number be X and Y
X square + Y square is equal to 233 ...(1)
now ,
x=2Y-3.....(2)

putting the value of x in equation 1
(2Y-3)^2 +Y^2 =233
4Y^2+9-12Y+Y^2=233
5Y^2-12Y-224=0


y=8 or 28
x=13 or 53 respectively