The sum of the squares of two positive integers is 208. If the square of the larger number is 18 times the smaller,
find the smaller number.
ritwikVerma:
the value seems incorrect
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Let a be the bigger number and b be the smaller numbers
a^2 + b^2 = 208
a^2 = 18b
18b + b^2 = 208
b^2 + 18b -208 = 0
(b+26)(b-8)=0
So b=8
So smaller number is 8
a^2 + b^2 = 208
a^2 = 18b
18b + b^2 = 208
b^2 + 18b -208 = 0
(b+26)(b-8)=0
So b=8
So smaller number is 8
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