Math, asked by Shreeyaharidas6410, 1 year ago

The sum of the squares of two positive integers is 208. If the square of the larger number is 18 times the smaller,
find the smaller number.


ritwikVerma: the value seems incorrect

Answers

Answered by shameemamk
10
Let a be the bigger number and b be the smaller numbers
a^2 + b^2 = 208
a^2 = 18b
18b + b^2 = 208
b^2 + 18b -208 = 0
(b+26)(b-8)=0
So b=8

So smaller number is 8


Answered by akshayaa58
2

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