Question

The sum of the there and shah terms of an anthmetic progression is 24

Answer 1

Step-by-step explanation:

general form of an Arithmetic Progression is a, a + d, a + 2d, a + 3d and so on. Thus nth term of an AP series is Tn = a + (n - 1) d, where Tn = nth term and a = first term. Here d = common difference = Tn - Tn-1. The sum of n terms is also equal to the formula where l is the last term.

Answer 2

Answer:

33

Step-by-step explanation:

a3= a+ 2d

a7= a+6d

a+2d = 12

a + 6d = 24

subtract them:

4d = 12

d = 3

back into the first: a + 6 = 12, a = 6

term(10) = a + 9d = 6 + 27 = 33