Question

The sum of the three consecutive integers exceed the middle integer by 6. Find the integers. *​

Answer 1

Answer:

Let the two consecutive positive integers be x and x+1

x2+(x+1)2−x(x+1)=91

x2+x−90=0

(x+10)(x−9)=0

x=−10 or 9.

As x is positive x=9

Hence the two consecutive positive integers are 9 and 10.

Answer 2

Answer:

let the integer be a,a+1,a+2

sum be a+1-6=a-5

a+a+1a+2=a-5

solve the equation