Question

the sum of the three consecutive numbers ina.p is 21 and their product is 231 find the numbers

Answer 1

hope this helps u. ..... ....

Answer 2

Here is your solution

let,

Three numbers be a,a-d,a+d

so a+a-d+a+d = 21

a = 7

A/q
(a)(a-d)(a+d) = 231

(7)(7-d)(7+d) = 231

49- d2 = 231/7

d2 = 16

therefore d = +4 or - 4

so no(s) r : 3, 7 and 10 or 10, 7 and 3

hope it helps you