the sum of the three terms which are in an arithematic progression is 33.if the product of the first and third terms exceeds the second term by 29 find the AP
Answers
Answer:-
Let the numbers in AP be a - d , a , a + d .
Given :
Sum of the numbers = 33
→ a - d + a + a + d = 33
→ 3a = 33
→ a = 33/3
→ a = 11.
And,
The product of the first term and last term exceeds the second term by 29.
→ (a + d) (a - d) = a + 29
→ a² - d² = a + 29
→ (11)² - d² = 11 + 29
→ 121 - d² = 40
→ - d² = 40 - 121
→ d² = 81
→ d = 9
We know that,
General form of an AP is a , a + d , a + 2d...
Hence, Our required AP is 11 , 20, 29...
Answer:
Step-by-step explanation:
Let the numbers in AP be a - d , a , a + d .
Given :
Sum of the numbers = 33
→ a - d + a + a + d = 33
→ 3a = 33
→ a = 33/3
→ a = 11.
And,
The product of the first term and last term exceeds the second term by 29.
→ (a + d) (a - d) = a + 29
→ a² - d² = a + 29
→ (11)² - d² = 11 + 29
→ 121 - d² = 40
→ - d² = 40 - 121
→ d² = 81
→ d = 9
We know that,
General form of an AP is a , a + d , a + 2d...
Hence, Our required AP is 11 , 20, 29...