Question

The sum of the twice of x and thrice of y is divided by difference of the x and y, then it is respectively
​

Answer 1

the answer should be 2x+3y/x-y

Answer 2

The required value is $\dfrac{2x+3y}{x-y}$

Step-by-step explanation:

Since we have given that

Twice of x = $2x$

Thrice of y = 3y

Sum would be $2x+3y$

Difference = $x-y$

so, when sum is divided by difference, we get that

$\dfrac{2x+3y}{x-y}$

Hence, the required value is $\dfrac{2x+3y}{x-y}$

# learn more:

The sum of the twice of x and

thrice of y is divided by different

of x and y, then it is respectively​

https://brainly.in/question/16317795