The sum of the two digit no. is 12. The no. Obtained by interchanging the two digit exceed the given no. by 18.find the no.
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Answered by
3
let the digitz b x and y
x+y=12
the two digit no..10x+y
interchangd no... 10y+x
10x+y+18=10y+x
9x-9y=18
x-y=2....(i)
x+y=12
using eliminatn methos u get the value of x and y as 5 n 7 ...thus the number is 57 or 75
x+y=12
the two digit no..10x+y
interchangd no... 10y+x
10x+y+18=10y+x
9x-9y=18
x-y=2....(i)
x+y=12
using eliminatn methos u get the value of x and y as 5 n 7 ...thus the number is 57 or 75
Answered by
1
let no be 10y+x according to question x+y=12......(i) & (10x+y)-(10y+x)=28 so x-y=2...(ii)
solving (i) &(ii) we get x=7 & y=5 so no is 75.
solving (i) &(ii) we get x=7 & y=5 so no is 75.
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