Question

the sum of the two digit number and the number formed by reversing the order of digit is 154 if the two digits differ by 4 find the number

Answer 1

Difference btw the 2 digits=4
Let one digit be x and the other will be x+4 (it can also be x-4. Either is correct)
the no.=10x +x+4
By reversing the digits, the no.= 10(x+4) +x
The sum = (10x +x+4)+(10x +40+x)
=11x+4+11x+40
22x+44=154
22x=154-44
22x=110
x=110÷22
Implies that,x=5
The no.=(10×5)+(5+4)
=50+9
The no. is=59

Answer 2

Answer:

can be 95 or 59

Step-by-step explanation:

Let the digit in ten's place be x and the digit in one's place be y

The number is 10x+y

The number obtained by reversing the order of digits is 10y+x

Given, 10x+y+10y+x=154

=>11x+11y=154

=>x+y=14       (1)

Also, x-y=4         (2)

Adding (1) and (2)

2x=18

=>x=9

Substituting x=9 in (1)

9+y=14

=>y=5

The number is 95. But if y-x=4, then the number is 59.

Therefore, the number can either be 95 or 59