Question

The sum of the zeroes of the bolynomial
Px) = 3K²+(2kt 1) x-Kt5 is equal to
the product of the Zeroes, then, find the
value of K.​

Answer 1

$p(k) = 3 {k}^{2} + (2k + 1)x - k + 5$

Let the Zeroes of this polynomial be $\alpha \beta$

A.T.Q.

$\alpha + \beta = \alpha \beta \\ \frac{ - b}{a} = \frac{c}{a} \\ - b = c$

$- (2k + 1) = - k + 5 \\ - 2k - 1 = - k + 5 \\ - 1 - 5 = - k + 2k \\ - 6 = k$