the sum of the zeroes of the polynomial 3x²- 10x +3
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The given equation is 3x2−10x+k=0
Let the two roots be α and β.
∴α+β=3−(−10)=310
Substituting α=31 in (1) we get β=3
Also, αβ=3k, →k=3
Thus, the other root b = 3 and the value of k =3
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