Question

the sum of the zeroes of the polynomials 3x^2-10x+3 is :-
(A) 10
(B) 10/3
(C) -10/3
(D) 1 ​

Answer 1

Answer:

10/3

Step-by-step explanation:

apply alpha + beeta = -b/a

b =-10

a =3

 alpha + beeta = -(-10)/3

                         = 10 /3

Answer 2

Answer:

Option b is the correct answer (It is solved in the uploaded photo)