Math, asked by anshu7363, 9 months ago

The sum of these consecutive multiples of. 11
is 363. Find these Multiples​

Answers

Answered by abhinavmishra2006
5

Answer:

Step-by-step explanation:

Three consecutive multiples are 110,121 and 132 which has the sum of 363. 33C = 363; C = 33, By substituting C = 33 in numbers 11C, 11(C – 1) and 11(C + 1) we get values 110, 121, 132.

Answered by pallavi7999
4

Answer:

(x+(x+11) +(x+12)) =363

33+3x=363

x=110

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