the sum of three AP is 21 and their products is 231.find the number .from 10th class solution
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let the numbers are a-d, a, a+d
ATQ
a-d+a+a+d=21
3a=21
a=7
Again
(a-d)a(a+d)=231
7-d . 7 . 7+d =231
49-d^2= 33
d^2= 16
d= +4,-4
find the 10th term= a+9d
ATQ
a-d+a+a+d=21
3a=21
a=7
Again
(a-d)a(a+d)=231
7-d . 7 . 7+d =231
49-d^2= 33
d^2= 16
d= +4,-4
find the 10th term= a+9d
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