The sum of three consecutive even integers is 36. find the smallest one
Answers
Answered by
43
let no. s be x,x+1,x+2.....
according to question......
x+x+1+x+2=36
3x+3=36
x=11.....
x=11, x+1=12, x+3=13. .
so, the smallest one is 11 .....
hope it helps you ......
please mark it as brainliest....
according to question......
x+x+1+x+2=36
3x+3=36
x=11.....
x=11, x+1=12, x+3=13. .
so, the smallest one is 11 .....
hope it helps you ......
please mark it as brainliest....
Answered by
19
.
Let x = smallest of three consecutive even integers
then
x+2 = second integer
x+4 = third
.
x + x+2 + x+4 = 36
3x + 6 = 36
3x = 30
x = 10 (answer)
Let x = smallest of three consecutive even integers
then
x+2 = second integer
x+4 = third
.
x + x+2 + x+4 = 36
3x + 6 = 36
3x = 30
x = 10 (answer)
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