Question

The sum of three consecutive even natural number is 48.find the greatest number of these numbers.

Answer 1

let, the smallest number be x, second x+2 and third x+4 then x+x+2+x+4=48 3x+6=48 3x=42 ,x=14 the greatest number =x+4=14+4=18

Answer 2

Here is your solution

Let ,
The first even number be x

The second even number be(x+2)

The third even number be (x+2)+2

Sum of three consecutive even numbers is 48

A/q

x + (x+2) + [(x+2)+2 = 48

x+x+x+2+2+2=48

3x + 6 = 48
3x = 48–6
3X= 42
X=14

The 3 consecutive number would be:-

The first even number => x = 14

The second even number =>(x+2) =14+2=16

The third even number => (x+2)+2=14+4=18

The largest amongst them is 16

Hope it helps you