the sum of three consecutive integars equals To the product of thtree consecutive integars. find the integars.
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answer will be 1,2,3
brownie62:
hey please cleary doubt
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Answer:
LET CONSECUTIVE NUMBERS ARE X , X+1 , X+2
GIVEN==>
SUM OF NUMBERS = PRODUCT OF NUMBERS
==> X+X+1+X+2 = X(X+1)(X+2)
==> 3X+3 = (X²+X)(X+2)
==> 3X+3 = X³+2X²+X²+2X
==> 3X+3 = X³+3X²+2X
==> 0 = X³+3X²+2X-3X-3
==> X³+3X²-X-3 = 0
LET VALUE OF X = 1
SO, PUTTING VALUE OF X IN EQ(1)
==> (1)³+3(1)²-(1)-3
==> 1+3-1-3
==>0
SO, X = 1
AND NUMBERS ARE :-
1 , 2 , 3
VERIFY
1+2+3 = 1×2×3
=> 6=6
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