Question

the sum of three consecutive integers is 198. what are the integers?​

Answer 1

Given:

☛ Sum of three consecutive integers is 198

To Find:

☛ the consecutive integers

Solution:

Let one consecutive integer be 2x + 1, the the other two integers are 2x + 2 , 2x + 3

According to question:

☛ sum of consecutive integers = 198

➜ 2x + 1 + 2x + 2 + 2x + 3 = 198

➜ 6x + 6 = 198

➜ 6x = 192

➜ x = 192/6

➜ x = 32

Now,

☛ 2x + 1

➜ 2(32) + 1

➜ 64 + 1

➜ 65

☛ 2x + 2

➜ 2(32) + 2

➜ 64 + 2

➜ 66

☛ 2x + 3

➜ 2(32) + 3

➜ 64 + 3

➜ 67

Hence, The consecutive integers are 65 , 66 and 67.

Answer 2

Answer:

hey mate , the three consecutive integers are 65,66,67 which have a total sum of 198 .

Step-by-step explanation:

here we will use algebra to find three consecutive integers whose sum is 198 , we start by assigning X to the first integer , since they are consecutive it means that the second number will be X+ 1 and so the third is X + 2 .

==> (x ) + (x+1) + (x+2) = 198

=> x+ x + 1 + x + 2 = 198

=>3x + 3 = 198

=> 3x = 198 - 3

=>3x = 195

=> x = 195/3

=> x = 65

so we found our first number which is 65 .

to find the second and third we have to fo as follow.

1st number = 65

2nd number= 65+ 1 = 66

3rd number = 65 + 2 = 67

so , by these calculations we found our answer.

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