the sum of three consecutive integers is -24. find the three integers
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13
x+x+1+x+2= -24
3x+3=-24
3x= -24+3
3x=-21
x=-21/3
x=-7
3x+3=-24
3x= -24+3
3x=-21
x=-21/3
x=-7
Answered by
11
The the first consecutive number = x
Sum of three consecutive numbers= -24 (i)
Also, sum of three consecutive numbers = x+(x+1)+(x+2) (ii)
(i) = (ii)
x+x+1+x+2 = -24
3x+3 = -24
3x = -24-3
3x = -27
x = -27/3
x = -9
So, x= -9, x+1=-8, x+2 = -7
Therefore, the three consecutive numbers are -9, -8, -7.
Sum of three consecutive numbers= -24 (i)
Also, sum of three consecutive numbers = x+(x+1)+(x+2) (ii)
(i) = (ii)
x+x+1+x+2 = -24
3x+3 = -24
3x = -24-3
3x = -27
x = -27/3
x = -9
So, x= -9, x+1=-8, x+2 = -7
Therefore, the three consecutive numbers are -9, -8, -7.
ymbahadur:
thank you.... i already got the solution.... anyway, thanks a lot....
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