Question

The sum of three consecutive integers is 246. Find the integers.

Answer 1

Let the three consecutive integers be

X , X+1 , X+2

A/Q

X + X + 1 + X + 2 = 246

3X + 3 = 246

3X = 246 - 3

3X = 243

X = 243/3

X = 81

Hence the three consecutive integers are
81 , 82 and 83.

Answer 2

Answer:

Concept:

    The numbers that come after one another are known as consecutive integers. They proceed sequentially or alphabetically. For instance, a group of natural numbers is a sequence of integers. In mathematics, the term "consecutive" refers to a continuous sequence or a series of integers where each succeeding number is one more than the one before it.

• The mean and median in an array of successive integers (or in numbers) are both identical. In the event that x is an integer, then x + 1 and x + 2 are also integers

Step-by-step explanation:

Given:

The sum of three consecutive integers is 246.

To find:

The value of integers.

Solution:

Let us take the three consecutive integers are x, x+1, x+2.

Their sum =246.

so, we can write  

⇒  x+x+1+x+2 = 246

⇒  3x+3 = 246

⇒  3x = 246-3

⇒  3x = 243

⇒  x = $\frac{243}{3}$

⇒  x = 81

x+1 = 81+1

     = 82

x+2= 81+2

     =83

Therefore the three consecutive integers of x, x+1, x+2 is 81,82,83.

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Answer 3

Answer:

Concept:

    The numbers that come after one another are known as consecutive integers. They proceed sequentially or alphabetically. For instance, a group of natural numbers is a sequence of integers. In mathematics, the term "consecutive" refers to a continuous sequence or a series of integers where each succeeding number is one more than the one before it.

• The mean and median in an array of successive integers (or in numbers) are both identical. In the event that x is an integer, then x + 1 and x + 2 are also integers

Step-by-step explanation:

Given:

The sum of three consecutive integers is 246.

To find:

The value of integers.

Solution:

Let us take the three consecutive integers are x, x+1, x+2.

Their sum =246.

so, we can write  

⇒  x+x+1+x+2 = 246

⇒  3x+3 = 246

⇒  3x = 246-3

⇒  3x = 243

⇒  x = $\frac{243}{3}$

⇒  x = 81

x+1 = 81+1

     = 82

x+2= 81+2

     =83

Therefore the three consecutive integers of x, x+1, x+2 is 81,82,83.

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